4.9x^2+13x-1.7=0

Solution for 4.9x^2+13x-1.7=0 equation:

4.9x^2+13x-1.7=0

a = 4.9; b = 13; c = -1.7;
Δ = b2-4ac
Δ = 132-4·4.9·(-1.7)
Δ = 202.32
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{202.32}}{2*4.9}=\frac{-13-\sqrt{202.32}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{202.32}}{2*4.9}=\frac{-13+\sqrt{202.32}}{9.8}
$